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Extract more than nine arguments that occur periodically in a sentence to use in macros in order to typset
How to define a command that takes more than 9 argumentsmacros that won't accept other macros as argumentsusing more than 2 arguments in a pgfplots styleUsing mathpalette with macros that take more argumentsUsing forcsvlist with macros that take more than one argumentHow to define a command that takes more than 18 argumentsHow to create a macro that creates other macros (that takes arguments)?How to create a table macro that takes more than 10 argumentsMacro with more than 9 argumentsDifferent command definitions with more than one optional arguments arguments
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
|
show 1 more comment
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.
– Guido Jorg
1 hour ago
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
1 hour ago
Without knowing the rules for applyingformit's really difficult to answer.
– egreg
1 hour ago
Suppose it'semphbut delayed expansion untilabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...stage reached is preferred. If not possible, then simply assumeemphstrictly speaking and can be expanded during each loop, though not as general.
– Guido Jorg
1 hour ago
@GuidoJorg I'm not asking whatformshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.
– egreg
1 hour ago
|
show 1 more comment
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
macros tex-core parsing
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
edited 1 hour ago
Guido Jorg
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
asked 1 hour ago
Guido JorgGuido Jorg
1,14931344
1,14931344
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.
– Guido Jorg
1 hour ago
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
1 hour ago
Without knowing the rules for applyingformit's really difficult to answer.
– egreg
1 hour ago
Suppose it'semphbut delayed expansion untilabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...stage reached is preferred. If not possible, then simply assumeemphstrictly speaking and can be expanded during each loop, though not as general.
– Guido Jorg
1 hour ago
@GuidoJorg I'm not asking whatformshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.
– egreg
1 hour ago
|
show 1 more comment
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.
– Guido Jorg
1 hour ago
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
1 hour ago
Without knowing the rules for applyingformit's really difficult to answer.
– egreg
1 hour ago
Suppose it'semphbut delayed expansion untilabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...stage reached is preferred. If not possible, then simply assumeemphstrictly speaking and can be expanded during each loop, though not as general.
– Guido Jorg
1 hour ago
@GuidoJorg I'm not asking whatformshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.
– egreg
1 hour ago
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 and funabc1 EDF1 xyz1 and funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.– Guido Jorg
1 hour ago
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 and funabc1 EDF1 xyz1 and funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.– Guido Jorg
1 hour ago
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
1 hour ago
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
1 hour ago
Without knowing the rules for applying
form it's really difficult to answer.– egreg
1 hour ago
Without knowing the rules for applying
form it's really difficult to answer.– egreg
1 hour ago
Suppose it's
emph but delayed expansion until abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ... stage reached is preferred. If not possible, then simply assume emph strictly speaking and can be expanded during each loop, though not as general.– Guido Jorg
1 hour ago
Suppose it's
emph but delayed expansion until abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ... stage reached is preferred. If not possible, then simply assume emph strictly speaking and can be expanded during each loop, though not as general.– Guido Jorg
1 hour ago
@GuidoJorg I'm not asking what
form should do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.– egreg
1 hour ago
@GuidoJorg I'm not asking what
form should do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.– egreg
1 hour ago
|
show 1 more comment
3 Answers
3
active
oldest
votes
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered 39 mins ago
egregegreg
728k8819243235
add a comment |
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the lettersxyzin order to decide whether or not to applyformto it??
– Steven B. Segletes
1 hour ago
|
show 1 more comment
Here's a LuaLaTeX-based solution. It employs Lua's powerful string.gsub function to the argument of the fun macro, to encase the third word of each group of five words -- where "word" is any combination of characters and digits delimited by whitespace -- in the argument of fun in a form... "wrapper".
Because luastringN (where N stands for "no expansion") is used in the argument of fun, the argument of fun is not expaneded prior to being passed to the Lua function that does all of the work.
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' env. and `luastringN` macro
%% Lua-side code
beginluacode
function do_fun ( s )
tex.sprint ( ( s:gsub (
"(%w+%s*%w+%s*)(%w+)(%s*%w+%s*%w+%s-)" ,
"%1\form%2%3" ) ) )
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastringN#1)
newcommandform[1]emph#1
begindocument
noindent
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl
abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl
abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl
abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl
abc13 EDF13 xyz13 efg jkl abc14 EDF14 xyz14 efg jkl abc15 EDF15 xyz15 efg jkl
abc16 EDF16 xyz16 efg jkl abc17 EDF17 xyz17 efg jkl
enddocument
answered 1 hour ago
MicoMico
284k31388777
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
add a comment |
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3 Answers
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3 Answers
3
active
oldest
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active
oldest
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active
oldest
votes
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered 39 mins ago
egregegreg
728k8819243235
add a comment |
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered 39 mins ago
egregegreg
728k8819243235
add a comment |
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered 39 mins ago
egregegreg
728k8819243235
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered 39 mins ago
egregegreg
728k8819243235
answered 39 mins ago
egregegreg
728k8819243235
answered 39 mins ago
egregegreg
728k8819243235
answered 39 mins ago
egregegreg
728k8819243235
728k8819243235
add a comment |
add a comment |
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the lettersxyzin order to decide whether or not to applyformto it??
– Steven B. Segletes
1 hour ago
|
show 1 more comment
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the lettersxyzin order to decide whether or not to applyformto it??
– Steven B. Segletes
1 hour ago
|
show 1 more comment
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
edited 1 hour ago
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
answered 1 hour ago
Steven B. SegletesSteven B. Segletes
159k9204412
159k9204412
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the lettersxyzin order to decide whether or not to applyformto it??
– Steven B. Segletes
1 hour ago
|
show 1 more comment
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the lettersxyzin order to decide whether or not to applyformto it??
– Steven B. Segletes
1 hour ago
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
1 hour ago
The result looking for is what would be printed had
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ... been entered manually. When in fact funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)– Guido Jorg
1 hour ago
The result looking for is what would be printed had
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ... been entered manually. When in fact funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)– Guido Jorg
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the letters
xyz in order to decide whether or not to apply form to it??– Steven B. Segletes
1 hour ago
@GuidoJorg If I understand what you are asking, the macro looks for anything starting with the letters
xyz in order to decide whether or not to apply form to it??– Steven B. Segletes
1 hour ago
|
show 1 more comment
Here's a LuaLaTeX-based solution. It employs Lua's powerful string.gsub function to the argument of the fun macro, to encase the third word of each group of five words -- where "word" is any combination of characters and digits delimited by whitespace -- in the argument of fun in a form... "wrapper".
Because luastringN (where N stands for "no expansion") is used in the argument of fun, the argument of fun is not expaneded prior to being passed to the Lua function that does all of the work.
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' env. and `luastringN` macro
%% Lua-side code
beginluacode
function do_fun ( s )
tex.sprint ( ( s:gsub (
"(%w+%s*%w+%s*)(%w+)(%s*%w+%s*%w+%s-)" ,
"%1\form%2%3" ) ) )
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastringN#1)
newcommandform[1]emph#1
begindocument
noindent
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl
abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl
abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl
abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl
abc13 EDF13 xyz13 efg jkl abc14 EDF14 xyz14 efg jkl abc15 EDF15 xyz15 efg jkl
abc16 EDF16 xyz16 efg jkl abc17 EDF17 xyz17 efg jkl
enddocument
answered 1 hour ago
MicoMico
284k31388777
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
add a comment |
Here's a LuaLaTeX-based solution. It employs Lua's powerful string.gsub function to the argument of the fun macro, to encase the third word of each group of five words -- where "word" is any combination of characters and digits delimited by whitespace -- in the argument of fun in a form... "wrapper".
Because luastringN (where N stands for "no expansion") is used in the argument of fun, the argument of fun is not expaneded prior to being passed to the Lua function that does all of the work.
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' env. and `luastringN` macro
%% Lua-side code
beginluacode
function do_fun ( s )
tex.sprint ( ( s:gsub (
"(%w+%s*%w+%s*)(%w+)(%s*%w+%s*%w+%s-)" ,
"%1\form%2%3" ) ) )
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastringN#1)
newcommandform[1]emph#1
begindocument
noindent
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl
abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl
abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl
abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl
abc13 EDF13 xyz13 efg jkl abc14 EDF14 xyz14 efg jkl abc15 EDF15 xyz15 efg jkl
abc16 EDF16 xyz16 efg jkl abc17 EDF17 xyz17 efg jkl
enddocument
answered 1 hour ago
MicoMico
284k31388777
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
add a comment |
Here's a LuaLaTeX-based solution. It employs Lua's powerful string.gsub function to the argument of the fun macro, to encase the third word of each group of five words -- where "word" is any combination of characters and digits delimited by whitespace -- in the argument of fun in a form... "wrapper".
Because luastringN (where N stands for "no expansion") is used in the argument of fun, the argument of fun is not expaneded prior to being passed to the Lua function that does all of the work.
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' env. and `luastringN` macro
%% Lua-side code
beginluacode
function do_fun ( s )
tex.sprint ( ( s:gsub (
"(%w+%s*%w+%s*)(%w+)(%s*%w+%s*%w+%s-)" ,
"%1\form%2%3" ) ) )
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastringN#1)
newcommandform[1]emph#1
begindocument
noindent
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl
abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl
abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl
abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl
abc13 EDF13 xyz13 efg jkl abc14 EDF14 xyz14 efg jkl abc15 EDF15 xyz15 efg jkl
abc16 EDF16 xyz16 efg jkl abc17 EDF17 xyz17 efg jkl
enddocument
answered 1 hour ago
MicoMico
284k31388777
Here's a LuaLaTeX-based solution. It employs Lua's powerful string.gsub function to the argument of the fun macro, to encase the third word of each group of five words -- where "word" is any combination of characters and digits delimited by whitespace -- in the argument of fun in a form... "wrapper".
Because luastringN (where N stands for "no expansion") is used in the argument of fun, the argument of fun is not expaneded prior to being passed to the Lua function that does all of the work.
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' env. and `luastringN` macro
%% Lua-side code
beginluacode
function do_fun ( s )
tex.sprint ( ( s:gsub (
"(%w+%s*%w+%s*)(%w+)(%s*%w+%s*%w+%s-)" ,
"%1\form%2%3" ) ) )
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastringN#1)
newcommandform[1]emph#1
begindocument
noindent
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl
abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl
abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl
abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl
abc13 EDF13 xyz13 efg jkl abc14 EDF14 xyz14 efg jkl abc15 EDF15 xyz15 efg jkl
abc16 EDF16 xyz16 efg jkl abc17 EDF17 xyz17 efg jkl
enddocument
answered 1 hour ago
MicoMico
284k31388777
edited 54 mins ago
answered 1 hour ago
MicoMico
284k31388777
answered 1 hour ago
MicoMico
284k31388777
answered 1 hour ago
MicoMico
284k31388777
284k31388777
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
add a comment |
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
1 hour ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
44 mins ago
add a comment |
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funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.– Guido Jorg
1 hour ago
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
1 hour ago
Without knowing the rules for applying
formit's really difficult to answer.– egreg
1 hour ago
Suppose it's
emphbut delayed expansion untilabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...stage reached is preferred. If not possible, then simply assumeemphstrictly speaking and can be expanded during each loop, though not as general.– Guido Jorg
1 hour ago
@GuidoJorg I'm not asking what
formshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.– egreg
1 hour ago