Knights and Knaves question Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)About the island of Knights and KnavesAbout Knights and Knaves and their consistencyThe way to Acarien, with Knights and KnavesKnights , Knaves and Spies - Part 1Knights and knaves at a partyMeta Knights and Knaves Puzzle with HatsKnights, Knaves and Normals - the tough oneKnights Knaves and SpiesSolve the following knights and knaves problem
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Knights and Knaves question
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)About the island of Knights and KnavesAbout Knights and Knaves and their consistencyThe way to Acarien, with Knights and KnavesKnights , Knaves and Spies - Part 1Knights and knaves at a partyMeta Knights and Knaves Puzzle with HatsKnights, Knaves and Normals - the tough oneKnights Knaves and SpiesSolve the following knights and knaves problem
$begingroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
asked 2 hours ago
user58804user58804
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
asked 2 hours ago
user58804user58804
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
27 mins ago
add a comment |
$begingroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
asked 2 hours ago
user58804user58804
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
logical-deduction liars
asked 2 hours ago
user58804user58804
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
user58804user58804
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
user58804
asked 2 hours ago
user58804user58804
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
user58804user58804
212
asked 2 hours ago
user58804user58804
212
212
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user58804 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
27 mins ago
add a comment |
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
27 mins ago
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
27 mins ago
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
27 mins ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
edited 26 mins ago
Rubio♦
30.8k567189
answered 2 hours ago
JayJay
2,8742922
$endgroup$
add a comment |
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1 Answer
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1 Answer
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$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
edited 26 mins ago
Rubio♦
30.8k567189
answered 2 hours ago
JayJay
2,8742922
$endgroup$
add a comment |
$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
edited 26 mins ago
Rubio♦
30.8k567189
answered 2 hours ago
JayJay
2,8742922
$endgroup$
add a comment |
$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
edited 26 mins ago
Rubio♦
30.8k567189
answered 2 hours ago
JayJay
2,8742922
$endgroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
edited 26 mins ago
Rubio♦
30.8k567189
answered 2 hours ago
JayJay
2,8742922
edited 26 mins ago
Rubio♦
30.8k567189
edited 26 mins ago
Rubio♦
30.8k567189
edited 26 mins ago
Rubio♦
30.8k567189
30.8k567189
answered 2 hours ago
JayJay
2,8742922
answered 2 hours ago
JayJay
2,8742922
answered 2 hours ago
JayJay
2,8742922
2,8742922
add a comment |
add a comment |
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
27 mins ago