Decimal to roman pythonRoman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string

1960's book about a plague that kills all white people

Why does Arabsat 6A need a Falcon Heavy to launch

What is the word for reserving something for yourself before others do?

What's the difference between 'rename' and 'mv'?

I'm flying to France today and my passport expires in less than 2 months

I Accidentally Deleted a Stock Terminal Theme

Emailing HOD to enhance faculty application

UK: Is there precedent for the governments e-petition site changing the direction of a government decision?

Python: return float 1.0 as int 1 but float 1.5 as float 1.5

Etiquette around loan refinance - decision is going to cost first broker a lot of money

Why is it a bad idea to hire a hitman to eliminate most corrupt politicians?

Arrow those variables!

Could gravitational lensing be used to protect a spaceship from a laser?

How can I tell someone that I want to be his or her friend?

What is the intuition behind short exact sequences of groups; in particular, what is the intuition behind group extensions?

Should I tell management that I intend to leave due to bad software development practices?

Anagram holiday

What to put in ESTA if staying in US for a few days before going on to Canada

Today is the Center

Doing something right before you need it - expression for this?

Brothers & sisters

How much of data wrangling is a data scientist's job?

What does it mean to describe someone as a butt steak?

Why is the ratio of two extensive quantities always intensive?



Decimal to roman python


Roman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








5












$begingroup$


I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'

divide_list = [1000, 100, 10, 1]

def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman









share|improve this question









New contributor




Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$


















    5












    $begingroup$


    I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



    roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
    500: 'D', 900: 'CM', 1000: 'M'

    divide_list = [1000, 100, 10, 1]

    def not_in_dict(fixed_decimal, divide_num):
    sub_count = 0
    sub_roman_multi = roman_dict[divide_num]
    temp_decimal = fixed_decimal
    while temp_decimal not in roman_dict:
    temp_decimal -= divide_num
    sub_count += 1
    return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

    def decimal_to_roman(decimal):
    original_decimal = decimal
    roman = ""
    for divide_num in divide_list:
    if decimal >= divide_num:
    reminder = decimal//divide_num
    if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
    roman += roman_dict[(reminder*divide_num)]
    decimal -= reminder*divide_num
    else:
    roman += not_in_dict(reminder*divide_num, divide_num)
    decimal -= (reminder*divide_num)
    return str(original_decimal)+' = '+roman









    share|improve this question









    New contributor




    Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      5












      5








      5





      $begingroup$


      I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



      roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
      500: 'D', 900: 'CM', 1000: 'M'

      divide_list = [1000, 100, 10, 1]

      def not_in_dict(fixed_decimal, divide_num):
      sub_count = 0
      sub_roman_multi = roman_dict[divide_num]
      temp_decimal = fixed_decimal
      while temp_decimal not in roman_dict:
      temp_decimal -= divide_num
      sub_count += 1
      return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

      def decimal_to_roman(decimal):
      original_decimal = decimal
      roman = ""
      for divide_num in divide_list:
      if decimal >= divide_num:
      reminder = decimal//divide_num
      if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
      roman += roman_dict[(reminder*divide_num)]
      decimal -= reminder*divide_num
      else:
      roman += not_in_dict(reminder*divide_num, divide_num)
      decimal -= (reminder*divide_num)
      return str(original_decimal)+' = '+roman









      share|improve this question









      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



      roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
      500: 'D', 900: 'CM', 1000: 'M'

      divide_list = [1000, 100, 10, 1]

      def not_in_dict(fixed_decimal, divide_num):
      sub_count = 0
      sub_roman_multi = roman_dict[divide_num]
      temp_decimal = fixed_decimal
      while temp_decimal not in roman_dict:
      temp_decimal -= divide_num
      sub_count += 1
      return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

      def decimal_to_roman(decimal):
      original_decimal = decimal
      roman = ""
      for divide_num in divide_list:
      if decimal >= divide_num:
      reminder = decimal//divide_num
      if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
      roman += roman_dict[(reminder*divide_num)]
      decimal -= reminder*divide_num
      else:
      roman += not_in_dict(reminder*divide_num, divide_num)
      decimal -= (reminder*divide_num)
      return str(original_decimal)+' = '+roman






      python roman-numerals






      share|improve this question









      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 11 hours ago









      Graipher

      26.7k54092




      26.7k54092






      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 12 hours ago









      OfeksOfeks

      283




      283




      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          1 Answer
          1






          active

          oldest

          votes


















          8












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            9 hours ago











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            9 hours ago











          Your Answer





          StackExchange.ifUsing("editor", function ()
          return StackExchange.using("mathjaxEditing", function ()
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
          );
          );
          , "mathjax-editing");

          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "196"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );






          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.









          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          8












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            9 hours ago











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            9 hours ago















          8












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            9 hours ago











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            9 hours ago













          8












          8








          8





          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$



          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 8 hours ago

























          answered 11 hours ago









          GraipherGraipher

          26.7k54092




          26.7k54092











          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            9 hours ago











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            9 hours ago
















          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            9 hours ago











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            9 hours ago















          $begingroup$
          wow. looks so easy now, thank you. that's great.
          $endgroup$
          – Ofeks
          9 hours ago





          $begingroup$
          wow. looks so easy now, thank you. that's great.
          $endgroup$
          – Ofeks
          9 hours ago













          $begingroup$
          @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
          $endgroup$
          – Graipher
          9 hours ago




          $begingroup$
          @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
          $endgroup$
          – Graipher
          9 hours ago










          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.









          draft saved

          draft discarded


















          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.












          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.











          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.














          Thanks for contributing an answer to Code Review Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Jet Time Laivasto | Lähteet | Aiheesta muualla | NavigointivalikkoJet Time - The CompanyThe CompanyManagementJet Time aloittaa lauantaina Suomi-rekisterissä olevalla Boeing 737 -koneellaJettime Finland Fleet Details and HistoryJettime Fleet Details and HistoryRegional Jet OÜ takes over ATR production for SASJet Time Returns To Its Core BusinessYhtiön kotisivutlaajentamalla

          Olympian arkeologinen museo Sisällysluettelo Historia ja rakennus | Kokoelmat | Lähteet | Aiheesta muualla | Navigointivalikko37°38′36″N, 21°37′46″EInfobox OKArchaeological Museum of Olympia: HistoryArchaeological Museum of Olympia: DescriptionΜουσείο Ιστορίας των Ολυμπιακών Αγώνων της Αρχαιότητας: ΙστορικόArchaeological Museum of Olympia

          Äpy Sisällysluettelo Äpyt kautta historian | Esimerkkejä Äpy-huumorista | Katso myös | Kirjallisuutta | Aiheesta muualla | Navigointivalikkowww.äpy.fi